ora-0137
10.7 Quadratic FTRL and typed tangents
Let the mechanism regularizer be
Assume \(Q_s\succeq 0\). After accumulation, define
Then \(H_t\succ 0\), and exact-loss FTRL has the unique decision
At the same base decision, evidence and mechanism variations satisfy
and
where
Their joint first-order response is \(\dot x^F_{t+1}+\dot x^\rho _{t+1}\).
The first-order condition is
Differentiating gives
Since \(H_t\) is invertible,
Holding the mechanism fixed gives the evidence equation. Holding evidence fixed and differentiating \(\lambda M\) and \(-\lambda Mm\) gives the mechanism equation. Linearity of the differential gives the joint response after the two directions are based at the same decision.
Evidence variations of the form
lie in the kernel of the FTRL decision tangent.
The accumulated constant affects only the decision-independent scalar term in the quadratic objective. It is absent from the first-order condition and therefore from Proposition 10.6.
The tangent calculation occurs in the ambient vector space \(\operatorname {Sym}_d(\mathbb {R})\). If a loss Hessian lies on the boundary of the positive-semidefinite cone, not every ambient direction preserves convexity. An OCO intervention must therefore be restricted to the appropriate tangent cone when convexity preservation is part of the declaration. The readout remains smooth as long as the total \(H_t\) stays positive definite.